# 8.15. Beam Search¶

In Section 8.14, we discussed how to train an encoder-decoder with input and output sequences that are both of variable length. In this section, we are going to introduce how to use the encoder-decoder to predict sequences of the variable length.

As introduced previously when preparing the training dataset, we normally attach a special symbol “<eos>” after each sentence to indicate the termination of the sequence. We will continue to use this mathematical symbol in the discussion below. For ease of discussion, we assume that the output of the decoder is a sequence of text. Let the size of output text dictionary \(\mathcal{Y}\) (contains special symbol “<eos>”) be \(\left|\mathcal{Y}\right|\), and the maximum length of the output sequence be \(T'\). There are a total \(\mathcal{O}(\left|\mathcal{Y}\right|^{T'})\) types of possible output sequences. All the subsequences after the special symbol “<eos>” in these output sequences will be discarded. What is more, we continuously refer to the content vector as \(\mathbf{c}\), which encodes the information of all the hidden states.

## 8.15.1. Greedy Search¶

First, we will take a look at a simple solution: greedy search. For any timestep \(t'\) of the output sequence, we are going to search for the word with the highest conditional probability from \(|\mathcal{Y}|\) numbers of words, with

as the output. Once the “<eos>” symbol is detected, or the output sequence has reached its maximum length \(T'\), the output is completed.

As we mentioned in our discussion of the decoder, the conditional probability of generating an output sequence based on the input sequence is \(\prod_{t'=1}^{T'} \mathbb{P}(y_{t'} \mid y_1, \ldots, y_{t'-1}, \mathbf{c})\). We will take the output sequence with the highest conditional probability as the optimal sequence. The main problem with greedy search is that there is no guarantee that the optimal sequence will be obtained.

Take a look at the example below. We assume that there are four words “A”, “B”, “C”, and “<eos>” in the output dictionary. The four numbers under each timestep in Fig. 8.15.1 represent the conditional probabilities of generating “A”, “B”, “C”, and “<eos>” at that timestep respectively. At each timestep, greedy search selects the word with the highest conditional probability. Therefore, the output sequence “A”, “B”, “C”, and “<eos>” will be generated in Fig. 8.15.1. The conditional probability of this output sequence is \(0.5\times0.4\times0.4\times0.6 = 0.048\).

Now, we will look at another example shown in Fig. 8.15.2. Unlike in Fig. 8.15.1, the following figure Fig. 8.15.2 selects the word “C”, which has the second highest conditional probability at timestep 2. Since the output subsequences of timesteps 1 and 2, on which timestep 3 is based, are changed from “A” and “B” in Fig. 8.15.1 to “A” and “C” in Fig. 8.15.2, the conditional probability of each word generated at timestep 3 has also changed in Fig. 8.15.2. We choose the word “B”, which has the highest conditional probability. Now, the output subsequences of timestep 4 based on the first three timesteps are “A”, “C”, and “B”, which are different from “A”, “B”, and “C” in Fig. 8.15.1. Therefore, the conditional probability of generating each word in timestep 4 in Fig. 8.15.2 is also different from that in Fig. 8.15.1. We find that the conditional probability of the output sequence “A”, “C”, “B”, and “<eos>” at the current timestep is \(0.5\times0.3 \times0.6\times0.6=0.054\), which is higher than the conditional probability of the output sequence obtained by greedy search. Therefore, the output sequence “A”, “B”, “C”, and “<eos>” obtained by the greedy search is not an optimal sequence.

## 8.15.2. Exhaustive Search¶

If the goal is to obtain the optimal sequence, we may consider using exhaustive search: an exhaustive examination of all possible output sequences, which outputs the sequence with the highest conditional probability.

Although we can use an exhaustive search to obtain the optimal sequence, its computational overhead \(\mathcal{O}(\left|\mathcal{Y}\right|^{T'})\) is likely to be excessively high. For example, when \(|\mathcal{Y}|=10000\) and \(T'=10\), we will need to evaluate \(10000^{10} = 10^{40}\) sequences. This is next to impossible to complete. The computational overhead of greedy search is \(\mathcal{O}(\left|\mathcal{Y}\right|T')\), which is usually significantly less than the computational overhead of an exhaustive search. For example, when \(|\mathcal{Y}|=10000\) and \(T'=10\), we only need to evaluate \(10000\times10=1\times10^5\) sequences.

## 8.15.3. Beam Search¶

*Beam search* is an improved algorithm based on greedy search. It has a
hyper-parameter named *beam size*, \(k\). At timestep 1, we select
\(k\) words with the highest conditional probability to be the first
word of the \(k\) candidate output sequences. For each subsequent
timestep, we are going to select the \(k\) output sequences with the
highest conditional probability from the total of
\(k\left|\mathcal{Y}\right|\) possible output sequences based on the
\(k\) candidate output sequences from the previous timestep. These
will be the candidate output sequence for that timestep. Finally, we
will filter out the sequences containing the special symbol “<eos>” from
the candidate output sequences of each timestep and discard all the
subsequences after it to obtain a set of final candidate output
sequences.

Fig. 8.15.3 demonstrates the process of beam search with an example. Suppose that the vocabulary of the output sequence only contains five elements: \(\mathcal{Y} = \{A, B, C, D, E\}\) where one of them is a special symbol “<eos>”. Set beam size to 2, the maximum length of the output sequence to 3. At timestep 1 of the output sequence, suppose the words with the highest conditional probability \(\mathbb{P}(y_1 \mid \mathbf{c})\) are \(A\) and \(C\). At timestep 2, for all \(y_2 \in \mathcal{Y},\) we compute

Then at timestep 3, for all \(y_3 \in \mathcal{Y}\), we compute

and

and pick the largest two among these 10 values, say

As a result, we obtain 6 candidates output sequences: (1) \(A\); (2) \(C\); (3) \(A\), \(B\); (4) \(C\), \(E\); (5) \(A\), \(B\), \(D\); and (6) \(C\), \(E\), \(D\). In the end, we will get the set of final candidate output sequences based on these 6 sequences.

In the set of final candidate output sequences, we will take the sequence with the highest score as the output sequence from those below:

Here, \(L\) is the length of the final candidate sequence and the selection for \(\alpha\) is generally 0.75. The \(L^\alpha\) on the denominator is a penalty on the logarithmic addition scores for the longer sequences above. The computational overhead \(\mathcal{O}(k\left|\mathcal{Y}\right|T')\) of the beam search can be obtained through analysis, which is between greedy search and exhaustive search. In addition, greedy search can be treated as a beam search with a beam size of 1. Beam search strikes a balance between computational overhead and search quality using a flexible beam size of \(k\).

## 8.15.4. Summary¶

Methods for predicting variable length sequences include greedy search, exhaustive search, and beam search.

Beam search strikes a balance between computational overhead and search quality using a flexible beam size.

## 8.15.5. Exercises¶

Can we treat an exhaustive search as a beam search with a special beam size? Why?

We used language models to generate sentences in Section 8.5. Which kind of search does this output use? Can you improve it?